Optimal. Leaf size=117 \[ -\frac{12 d^2 (c+d x) \text{PolyLog}\left (2,-e^{e+f x}\right )}{a f^3}+\frac{12 d^3 \text{PolyLog}\left (3,-e^{e+f x}\right )}{a f^4}-\frac{6 d (c+d x)^2 \log \left (e^{e+f x}+1\right )}{a f^2}+\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}+\frac{(c+d x)^3}{a f} \]
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Rubi [A] time = 0.272983, antiderivative size = 117, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.35, Rules used = {3318, 4184, 3718, 2190, 2531, 2282, 6589} \[ -\frac{12 d^2 (c+d x) \text{PolyLog}\left (2,-e^{e+f x}\right )}{a f^3}+\frac{12 d^3 \text{PolyLog}\left (3,-e^{e+f x}\right )}{a f^4}-\frac{6 d (c+d x)^2 \log \left (e^{e+f x}+1\right )}{a f^2}+\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}+\frac{(c+d x)^3}{a f} \]
Antiderivative was successfully verified.
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Rule 3318
Rule 4184
Rule 3718
Rule 2190
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{(c+d x)^3}{a+a \cosh (e+f x)} \, dx &=\frac{\int (c+d x)^3 \csc ^2\left (\frac{1}{2} (i e+\pi )+\frac{i f x}{2}\right ) \, dx}{2 a}\\ &=\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}-\frac{(3 d) \int (c+d x)^2 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right ) \, dx}{a f}\\ &=\frac{(c+d x)^3}{a f}+\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}-\frac{(6 d) \int \frac{e^{2 \left (\frac{e}{2}+\frac{f x}{2}\right )} (c+d x)^2}{1+e^{2 \left (\frac{e}{2}+\frac{f x}{2}\right )}} \, dx}{a f}\\ &=\frac{(c+d x)^3}{a f}-\frac{6 d (c+d x)^2 \log \left (1+e^{e+f x}\right )}{a f^2}+\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}+\frac{\left (12 d^2\right ) \int (c+d x) \log \left (1+e^{2 \left (\frac{e}{2}+\frac{f x}{2}\right )}\right ) \, dx}{a f^2}\\ &=\frac{(c+d x)^3}{a f}-\frac{6 d (c+d x)^2 \log \left (1+e^{e+f x}\right )}{a f^2}-\frac{12 d^2 (c+d x) \text{Li}_2\left (-e^{e+f x}\right )}{a f^3}+\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}+\frac{\left (12 d^3\right ) \int \text{Li}_2\left (-e^{2 \left (\frac{e}{2}+\frac{f x}{2}\right )}\right ) \, dx}{a f^3}\\ &=\frac{(c+d x)^3}{a f}-\frac{6 d (c+d x)^2 \log \left (1+e^{e+f x}\right )}{a f^2}-\frac{12 d^2 (c+d x) \text{Li}_2\left (-e^{e+f x}\right )}{a f^3}+\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}+\frac{\left (12 d^3\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(-x)}{x} \, dx,x,e^{2 \left (\frac{e}{2}+\frac{f x}{2}\right )}\right )}{a f^4}\\ &=\frac{(c+d x)^3}{a f}-\frac{6 d (c+d x)^2 \log \left (1+e^{e+f x}\right )}{a f^2}-\frac{12 d^2 (c+d x) \text{Li}_2\left (-e^{e+f x}\right )}{a f^3}+\frac{12 d^3 \text{Li}_3\left (-e^{e+f x}\right )}{a f^4}+\frac{(c+d x)^3 \tanh \left (\frac{e}{2}+\frac{f x}{2}\right )}{a f}\\ \end{align*}
Mathematica [A] time = 2.05863, size = 154, normalized size = 1.32 \[ \frac{2 \cosh \left (\frac{1}{2} (e+f x)\right ) \left (2 \cosh \left (\frac{1}{2} (e+f x)\right ) \left (6 d^2 \left (f (c+d x) \text{PolyLog}\left (2,-e^{-e-f x}\right )+d \text{PolyLog}\left (3,-e^{-e-f x}\right )\right )-\frac{f^3 (c+d x)^3}{e^e+1}-3 d f^2 (c+d x)^2 \log \left (e^{-e-f x}+1\right )\right )+f^3 \text{sech}\left (\frac{e}{2}\right ) (c+d x)^3 \sinh \left (\frac{f x}{2}\right )\right )}{a f^4 (\cosh (e+f x)+1)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.119, size = 325, normalized size = 2.8 \begin{align*} -2\,{\frac{{d}^{3}{x}^{3}+3\,c{d}^{2}{x}^{2}+3\,{c}^{2}dx+{c}^{3}}{fa \left ({{\rm e}^{fx+e}}+1 \right ) }}-6\,{\frac{{c}^{2}d\ln \left ({{\rm e}^{fx+e}}+1 \right ) }{a{f}^{2}}}+6\,{\frac{{c}^{2}d\ln \left ({{\rm e}^{fx+e}} \right ) }{a{f}^{2}}}+6\,{\frac{{d}^{3}{e}^{2}\ln \left ({{\rm e}^{fx+e}} \right ) }{{f}^{4}a}}+2\,{\frac{{d}^{3}{x}^{3}}{af}}-6\,{\frac{{d}^{3}{e}^{2}x}{a{f}^{3}}}-4\,{\frac{{d}^{3}{e}^{3}}{{f}^{4}a}}-6\,{\frac{{d}^{3}\ln \left ({{\rm e}^{fx+e}}+1 \right ){x}^{2}}{a{f}^{2}}}-12\,{\frac{{d}^{3}{\it polylog} \left ( 2,-{{\rm e}^{fx+e}} \right ) x}{a{f}^{3}}}+12\,{\frac{{d}^{3}{\it polylog} \left ( 3,-{{\rm e}^{fx+e}} \right ) }{{f}^{4}a}}-12\,{\frac{c{d}^{2}e\ln \left ({{\rm e}^{fx+e}} \right ) }{a{f}^{3}}}+6\,{\frac{c{d}^{2}{x}^{2}}{af}}+12\,{\frac{c{d}^{2}ex}{a{f}^{2}}}+6\,{\frac{c{d}^{2}{e}^{2}}{a{f}^{3}}}-12\,{\frac{c{d}^{2}\ln \left ({{\rm e}^{fx+e}}+1 \right ) x}{a{f}^{2}}}-12\,{\frac{c{d}^{2}{\it polylog} \left ( 2,-{{\rm e}^{fx+e}} \right ) }{a{f}^{3}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.61465, size = 308, normalized size = 2.63 \begin{align*} 6 \, c^{2} d{\left (\frac{x e^{\left (f x + e\right )}}{a f e^{\left (f x + e\right )} + a f} - \frac{\log \left ({\left (e^{\left (f x + e\right )} + 1\right )} e^{\left (-e\right )}\right )}{a f^{2}}\right )} + \frac{2 \, c^{3}}{{\left (a e^{\left (-f x - e\right )} + a\right )} f} - \frac{2 \,{\left (d^{3} x^{3} + 3 \, c d^{2} x^{2}\right )}}{a f e^{\left (f x + e\right )} + a f} - \frac{12 \,{\left (f x \log \left (e^{\left (f x + e\right )} + 1\right ) +{\rm Li}_2\left (-e^{\left (f x + e\right )}\right )\right )} c d^{2}}{a f^{3}} - \frac{6 \,{\left (f^{2} x^{2} \log \left (e^{\left (f x + e\right )} + 1\right ) + 2 \, f x{\rm Li}_2\left (-e^{\left (f x + e\right )}\right ) - 2 \,{\rm Li}_{3}(-e^{\left (f x + e\right )})\right )} d^{3}}{a f^{4}} + \frac{2 \,{\left (d^{3} f^{3} x^{3} + 3 \, c d^{2} f^{3} x^{2}\right )}}{a f^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 2.06006, size = 1008, normalized size = 8.62 \begin{align*} \frac{2 \,{\left (d^{3} e^{3} - 3 \, c d^{2} e^{2} f + 3 \, c^{2} d e f^{2} - c^{3} f^{3} +{\left (d^{3} f^{3} x^{3} + 3 \, c d^{2} f^{3} x^{2} + 3 \, c^{2} d f^{3} x + d^{3} e^{3} - 3 \, c d^{2} e^{2} f + 3 \, c^{2} d e f^{2}\right )} \cosh \left (f x + e\right ) - 6 \,{\left (d^{3} f x + c d^{2} f +{\left (d^{3} f x + c d^{2} f\right )} \cosh \left (f x + e\right ) +{\left (d^{3} f x + c d^{2} f\right )} \sinh \left (f x + e\right )\right )}{\rm Li}_2\left (-\cosh \left (f x + e\right ) - \sinh \left (f x + e\right )\right ) - 3 \,{\left (d^{3} f^{2} x^{2} + 2 \, c d^{2} f^{2} x + c^{2} d f^{2} +{\left (d^{3} f^{2} x^{2} + 2 \, c d^{2} f^{2} x + c^{2} d f^{2}\right )} \cosh \left (f x + e\right ) +{\left (d^{3} f^{2} x^{2} + 2 \, c d^{2} f^{2} x + c^{2} d f^{2}\right )} \sinh \left (f x + e\right )\right )} \log \left (\cosh \left (f x + e\right ) + \sinh \left (f x + e\right ) + 1\right ) + 6 \,{\left (d^{3} \cosh \left (f x + e\right ) + d^{3} \sinh \left (f x + e\right ) + d^{3}\right )}{\rm polylog}\left (3, -\cosh \left (f x + e\right ) - \sinh \left (f x + e\right )\right ) +{\left (d^{3} f^{3} x^{3} + 3 \, c d^{2} f^{3} x^{2} + 3 \, c^{2} d f^{3} x + d^{3} e^{3} - 3 \, c d^{2} e^{2} f + 3 \, c^{2} d e f^{2}\right )} \sinh \left (f x + e\right )\right )}}{a f^{4} \cosh \left (f x + e\right ) + a f^{4} \sinh \left (f x + e\right ) + a f^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{c^{3}}{\cosh{\left (e + f x \right )} + 1}\, dx + \int \frac{d^{3} x^{3}}{\cosh{\left (e + f x \right )} + 1}\, dx + \int \frac{3 c d^{2} x^{2}}{\cosh{\left (e + f x \right )} + 1}\, dx + \int \frac{3 c^{2} d x}{\cosh{\left (e + f x \right )} + 1}\, dx}{a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d x + c\right )}^{3}}{a \cosh \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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